{"id":20599,"date":"2019-09-20T01:19:21","date_gmt":"2019-09-20T06:19:21","guid":{"rendered":"http:\/\/www.kaptest.com\/blog\/prep\/?p=20599"},"modified":"2020-09-11T20:40:35","modified_gmt":"2020-09-11T20:40:35","slug":"ssat-word-problem-practice-questions","status":"publish","type":"post","link":"https:\/\/wpapp.kaptest.com\/study\/ssat\/ssat-word-problem-practice-questions\/","title":{"rendered":"SSAT Word Problem Practice Questions"},"content":{"rendered":"<p>Now that you&#8217;ve learned some of the <a title=\"SSAT word problem strategies\" href=\"https:\/\/www.kaptest.com\/study\/ssat\/the-ssat-word-problems\/#toggle-id-2\">strategies for the Word Problem section of the SSAT<\/a>, test your knowledge with some practice questions!<br \/>\n<div class='quizz-container' data-quiz='468786' data-width='100%' data-height='auto' data-auto-redirect='true'><\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-0  el_before_av_toggle_container  avia-builder-el-first '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 1<\/strong><br \/>\nThe original price of a television decreases by 20 percent. By what percent must the discounted price increase to reach its original value?<br \/>\n(A) 15%<br \/>\n(B) 20%<br \/>\n(C) 25%<br \/>\n(D) 30%<br \/>\n(E) 40%<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-1  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-1\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-1\">Answer 1<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-1\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>C:\u00a0<\/strong>It is important to note that while the value of the television decreases and increases by the same dollar amount, it doesn\u2019t increase and decrease by the same percent. Let\u2019s pick $100 for the price of the television. If the price decreases by 20%, and since 20% of $100 is $20, the price decreases by $20. The new price is $100 \u2212 $20, or $80. For the new\u00a0price to reach the original price ($100), it must be increased by $20. Twenty dollars is 1 4 of 80, or 25% of $80. The new price must be increased by 25%, choice (C).<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-2  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 2<\/strong><br \/>\nA worker earns $15 an hour for the first 40 hours he works each week and one and a half times this much for every hour over 40 hours. If he earned $667.50 for one week\u2019s work, how many hours did he work?<br \/>\n(A) 40<br \/>\n(B) 41<br \/>\n(C) 42<br \/>\n(D) 43<br \/>\n(E) 44<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-3  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-2\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-2\">Answer 2<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-2\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>D:\u00a0<\/strong>Run the answer choices through the information in the stem to see which one gives a total of $667.50. Since the answer choices are in numerical order, start with the middle choice, (C). If he works for 42 hours, he earns $15 per hour for the first 40 hours, or $600, and he earns 1 1 2 times his normal rate for the two extra hours. So 3\/2 times $15 is $22.50 per hour, and since he worked 2 hours at that rate, he made an additional $45. The total is $645, which isn\u2019t enough. So (C) is too small, as are (A) and (B). Now try (D). He still earns $600 for the first 40 hours, but now you have to multiply the overtime rate, $22.50, by 3, which gives you $67.50. The total is $667.50, which means that (D) is correct. Another way to approach the question is to see that for the first 40 hours, the worker earns $15 an hour: 40 hours \u00d7 $15 an hour = $600. For any additional hours, he earns one and a half times $15. So 1.5 \u00d7 $15 = $22.50 per hour. If he earned $667.50 in one week, $600 was earned in the first 40 hours and the remaining $67.50 was earned working additional hours. To find out how many additional hours the worker worked, divide the amount earned ($67.50) by the amount earned per hour ($22.50). And $67.50 \u00f7 $22.50 = 3. So 40 hours + 3 additional hours equals 43 hours.<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-4  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 3<\/strong><br \/>\nLiza has 40 less than three times the number of books that Janice has. If\u00a0<em>B<\/em>\u00a0is equal to the number of books that Janice has, which of the following expressions shows the total number of books that Liza and Janice have together?<br \/>\n(A) 3<em>B<\/em>\u00a0\u2212 40<br \/>\n(B) 3<em>B<\/em>\u00a0+ 40<br \/>\n(C) 4<em>B<\/em>\u00a0\u2212 40<br \/>\n(D) 4<em>B<\/em><br \/>\n(E) 4<em>B<\/em>\u00a0+ 40<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-5  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-3\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-3\">Answer 3<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-3\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>C:\u00a0<\/strong>This is a straightforward translation problem. You\u2019re told that Janice has <em>B<\/em> books. Liza has 40 less than three times the number of books Janice has, which you can translate as L = 3<em>B<\/em> \u2212 40. The total number they have together equals <em>B<\/em> + (3<em>B<\/em> \u2212 40), or 4<em>B<\/em> \u2212 40.<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-6  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 4<\/strong><br \/>\nYesterday, a store sold 8 times as many hats as it sold coats. It also sold 3 times as many sweaters as it sold coats. What could be the total number of hats, sweaters, and coats that were sold?<br \/>\n(A) 16<br \/>\n(B) 21<br \/>\n(C) 25<br \/>\n(D) 36<br \/>\n(E) 54<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-7  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-4\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-4\">Answer 4<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-4\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>D: <\/strong>Let x be the number of coats that the store sold yesterday. Keep in mind that x must be an integer. The store sold 8 times the number of hats as coats yesterday. So the store sold 8x hats. The store sold 3 times the number of sweaters as coats yesterday. So the store sold 3x sweaters. The total number of hats, sweaters, and coats that the store sold was 8x + 3x + x = 12x. Since x is an integer, 12x must be a multiple of 12. Only (D), 36, is a multiple of 12 (36 = 3 \u00d7 12).<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-8  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 5<\/strong><br \/>\nIf 3 added to 4 times a number is 11, the number must be<br \/>\n(A) 1<br \/>\n(B) 2<br \/>\n(C) 3<br \/>\n(D) 4<br \/>\n(E) 5<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-9  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-5\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-5\">Answer 5<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-5\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>B:\u00a0<\/strong>Let the number be <em>x<\/em>. Translating gives you 3 + 4<em>x<\/em> = 11. Therefore, 4<em>x<\/em> = 8 and <em>x<\/em> = 2.<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-10  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 6<\/strong><br \/>\nLiz worked 3 hours less than twice as many hours as Rachel did. If\u00a0<em>W<\/em>\u00a0is the number of hours Rachel worked, which of the following expressions shows the total number of hours worked by Liz and Rachel together?<br \/>\n(A) 2<em>W<\/em>\u00a0\u2212 3<br \/>\n(B) 2<em>W<\/em>\u00a0+ 3<br \/>\n(C) 3<em>W<\/em>\u00a0\u2212 3<br \/>\n(D) 3<em>W<\/em>\u00a0+ 3<br \/>\n(E) 4<em>W<\/em>\u00a0\u2212 2<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-11  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-6\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-6\">Answer 6<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-6\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>C:\u00a0<\/strong>Rachel worked <em>W<\/em> hours, and Liz worked 3 hours less than twice as many hours as Rachel, or 2<em>W<\/em> \u2212 3. Add these expressions to find the total number of hours worked by Liz and Rachel together: <em>W<\/em> + 2<em>W<\/em> \u2212 3 = 3<em>W<\/em> \u2212 3<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-no   avia-builder-el-12  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>\n<strong>Question 7<\/strong><br \/>\nFive less than 3 times a certain number is equal to twice the original number plus 7. What is the original number?<br \/>\n(A) 2<br \/>\n(B) 2 2\/5<br \/>\n(C) 6<br \/>\n(D) 11<br \/>\n(E) 12<\/p>\n<\/div><\/div><br \/>\n<div  class=\"togglecontainer   toggle_close_all  avia-builder-el-13  el_after_av_promobox  el_before_av_promobox \" >\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-7\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-7\">Answer 7<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-7\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p><strong>E:\u00a0<\/strong>Call the unknown number x. Five less than 3 times the number, or 3<em>x<\/em> \u2212 5, equals twice the original number plus 7, or 2<em>x<\/em> + 7. So 3<em>x<\/em> \u2212 5 = 2<em>x<\/em> + 7. Solve for <em>x<\/em>:<br \/>\n3<em>x<\/em> \u2212 5 = 2<em>x<\/em> + 7<br \/>\n<em>x<\/em> \u2212 5 = 7<br \/>\n<em>x<\/em> = 12<\/p>\n            <\/div>        <\/div>    <\/div><\/section>\n<\/div><br \/>\n\t<div   class='av_promobox  avia-button-yes   avia-builder-el-14  el_after_av_toggle_container  avia-builder-el-last '>\t\t<div class='avia-promocontent'><p>\nNeed some help prepping for the SSAT? Check out Kaplan&#8217;s study resources!<\/p>\n<\/div><div  class='avia-button-wrap avia-button-right ' ><a href='https:\/\/www.kaptest.com\/ssat'  class='avia-button  avia-color-theme-color   avia-icon_select-no avia-size-large avia-position-right '   ><span class='avia_iconbox_title' >SSAT Courses, Books, &amp; Tutoring<\/span><\/a><\/div><\/div><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Now that you&#8217;ve learned some of the strategies for the Word Problem section of the SSAT, test your knowledge with some practice questions!<\/p>\n","protected":false},"author":1,"featured_media":28826,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[381],"tags":[380],"_links":{"self":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/20599"}],"collection":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/comments?post=20599"}],"version-history":[{"count":1,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/20599\/revisions"}],"predecessor-version":[{"id":34125,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/20599\/revisions\/34125"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/media\/28826"}],"wp:attachment":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/media?parent=20599"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/categories?post=20599"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/tags?post=20599"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}