{"id":2415,"date":"2016-08-31T10:32:26","date_gmt":"2016-08-31T15:32:26","guid":{"rendered":"http:\/\/www.kaptest.com\/blog\/prep\/?p=2415"},"modified":"2026-09-29T17:22:22","modified_gmt":"2026-09-29T17:22:22","slug":"gre-quantitative-rates-and-work-question-practice","status":"publish","type":"post","link":"https:\/\/wpapp.kaptest.com\/study\/gre\/gre-quantitative-rates-and-work-question-practice\/","title":{"rendered":"GRE Quantitative: Rates and Work Question Practice"},"content":{"rendered":"<p>On the GRE, Rates and Work questions may appear in any of the Quantitative question formats: Multiple Choice, Numeric Entry, or Quantitative Comparisons. A \u201crate\u201d is anything\u00a0<em>per<\/em>\u00a0anything (miles per hour, laps per minute, gallons of paint per square inch of wall, etc.).<br \/>In the meantime, here are two formulas you should memorize to get these types of questions correct on your GRE test:<\/p>\n<ul>\n<li>The first GRE formula to memorize before your GRE test is: D = R x T. This stands for Distance = Rate x Time. It can also be rearranged as Time = Distance \/ Rate or as Rate = Distance \/ Time.<\/li>\n<li>The second formula you\u2019ll want to know is: Average Rate = Total Distance \/ Total Time. Average Rate may have the word \u201caverage\u201d in it, but remember that this is an entirely different concept from mathematical mean. Let\u2019s look at an example question:<\/li>\n<\/ul>\n<p>Let&#8217;s review some practice questions:<br \/>\u00a0<br \/><div  style='padding-bottom:10px; ' class='av-special-heading av-special-heading-h3    avia-builder-el-0  el_before_av_promobox  avia-builder-el-first  '><h3 class='av-special-heading-tag '  itemprop=\"headline\"  >GRE Quantitative: Rates and Work Practice Question<\/h3><div class='special-heading-border'><div class='special-heading-inner-border' ><\/div><\/div><\/div><br \/>\t<div  style='background:#ffffff;color:#444444;border-color:#444444;' class='av_promobox  avia-button-no   avia-builder-el-1  el_after_av_heading  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>1. Joanne drove 80 miles to see her mother. It took her 4 hours to get there. Then, she left her mother\u2019s and drove another 40 miles to visit her aunt, but this time went 40mph. What was her average speed for the whole trip?<\/p>\n<\/div><\/div><br \/><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-2  el_after_av_promobox  el_before_av_hr \" ><section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-1\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-1\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-1\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>Remember Average Speed = Total Distance \/ Total Time.<br \/>Joanne traveled 80 miles + 40 miles so the Total Distance was 120 miles. She drove for 4 hours + 1 hour (since 40 miles at 40mph would only be 1 hour) so the Total Time was 5 hours. 120\/5 = 24.<br \/>Therefore,<strong>\u00a0the average speed for the whole trip was 24 mph<\/strong>. Think of Average Speed as a weighted average. Joanne spent more time going 20mph than 40mph, so it makes sense that the Average Speed would be closer to 20mph.<\/p>\n            <\/div>        <\/div>    <\/div><\/section><\/div><br \/><div   class='hr hr-short hr-center   avia-builder-el-3  el_after_av_toggle_container  el_before_av_promobox '><span class='hr-inner ' ><span class='hr-inner-style'><\/span><\/span><\/div><br \/>Let\u2019s try another practice question.<br \/>\t<div  style='background:#ffffff;color:#444444;border-color:#444444;' class='av_promobox  avia-button-no   avia-builder-el-4  el_after_av_hr  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>2. Marion spent a day on a sightseeing trip in Tuscany. First she boarded a bus which went 15mph through a 30 mile section of the countryside. The bus then stopped for lunch in Florence before continuing on a 3 hour tour of the city&#8217;s sights at speed of 10mph. Finally, the bus left the city and drove 40 miles straight back to the hotel. Marion arrived back at her hotel exactly 2 hours after leaving Florence. What was the bus&#8217;s average rate for the entire journey?<\/p>\n<\/div><\/div><br \/><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-5  el_after_av_promobox  el_before_av_hr \" ><section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-2\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-2\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-2\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>To find the &#8220;Average Rate&#8221; of the bus, we know we will need to find the Total Distance and the Total Time, so let&#8217;s see how we can use the D = R x T formula to find the missing info.<br \/>For the first part of the trip, we know that 30 miles = 15mph x T, so we know that T = 2 hours.<br \/>For the middle part of the trip, we know that D = 10mph x 3 hours, so we know that D = 30 miles.<br \/>For the last part of the trip, we know that 40 miles = R x 2 hours, so we know that R = 20mph.<br \/>Now we can find the Total Distance and the Total Time.<br \/>Total Distance = 30 miles + 30 miles + 40miles = 100 miles.<br \/>Total Time = 2 hours + 3 hours + 2 hours = 7 hours.<br \/>So\u00a0<strong>the Average Rate = 100 miles\/ 7 hours = 14.28mph.<\/strong><\/p>\n            <\/div>        <\/div>    <\/div><\/section><\/div><br \/><div   class='hr hr-short hr-center   avia-builder-el-6  el_after_av_toggle_container  el_before_av_heading '><span class='hr-inner ' ><span class='hr-inner-style'><\/span><\/span><\/div><br \/><div  style='padding-bottom:10px; ' class='av-special-heading av-special-heading-h3    avia-builder-el-7  el_after_av_hr  el_before_av_promobox  '><h3 class='av-special-heading-tag '  itemprop=\"headline\"  >Converting Rates on the GRE<\/h3><div class='special-heading-border'><div class='special-heading-inner-border' ><\/div><\/div><\/div><br \/>Some\u00a0GRE\u00a0rate questions will be presented as Quantitative Comparisons and will require conversions. You won\u2019t be required to know complicated conversions (such as liters to gallons) but you must know a few basics chronological ones. There are 60 seconds in 1 minute, 60 minutes in 1 hour, 24 hours in a day, and 365 days in one year. For measurement, it\u2019s enough to know that a foot has 12 inches.<br \/>Let\u2019s look at this\u00a0question:<br \/>\t<div  style='background:#ffffff;color:#444444;border-color:#444444;' class='av_promobox  avia-button-no   avia-builder-el-8  el_after_av_heading  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>3.<\/p>\n<table>\n<tbody>\n<tr>\n<th>Column A<\/th>\n<th>Column B<\/th>\n<\/tr>\n<tr>\n<td>The number of seconds in 2 hours<\/td>\n<td>The number of days in 20 years<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>A. Quantity A is greater.<br \/>B. Quantity B is greater.<br \/>C. The two quantities are equal.<br \/>D. The relationship cannot be determined from the information given.<\/p>\n<\/div><\/div><br \/><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-9  el_after_av_promobox  el_before_av_hr \" ><section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-3\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-3\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-3\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>2 hours = 120 minutes = 7200 seconds<br \/>20 years\u00a0 = 365 days x 20 = 7300.<br \/><strong>Even without considering leap years, (B) will be greater.<\/strong><\/p>\n            <\/div>        <\/div>    <\/div><\/section><\/div><br \/><div   class='hr hr-short hr-center   avia-builder-el-10  el_after_av_toggle_container  el_before_av_promobox '><span class='hr-inner ' ><span class='hr-inner-style'><\/span><\/span><\/div><\/p>\n<h2>Solving GRE Work Problems with Combined Rates<\/h2>\n<p>To solve a GRE work problem, find how much of the job each person completes in one hour. Then add those rates to determine how quickly they work together.<\/p>\n<p>For example, Sheila takes 4 hours to clean a room, so she completes \u00bc of the job per hour. Her mom takes 3 hours to clean the same room, so she completes \u2153 of the job per hour.<\/p>\n<p>Together, their rate is:<\/p>\n<p><strong>\u00bc + \u2153 = 7\/12 of the job per hour<\/strong><\/p>\n<p>To find the time needed to finish one whole job, divide the job by their combined rate:<\/p>\n<p><strong>1 \u00f7 7\/12 = 12\/7 hours, or about 1 hour and 43 minutes<\/strong><\/p>\n<h3>Using Work Units to Simplify the Calculation<\/h3>\n<p>Another approach is to imagine the room-cleaning job as 12 equal work units. Choosing 12, a multiple of both 4 and 3, makes the rates easier to calculate:<\/p>\n<ul>\n<li>Sheila completes 12 units in 4 hours: <strong>3 units per hour<\/strong>.<\/li>\n<li>Her mom completes 12 units in 3 hours: <strong>4 units per hour<\/strong>.<\/li>\n<li>Together, they complete <strong>7 units per hour<\/strong>.<\/li>\n<\/ul>\n<p>The full job therefore takes <strong>12 \u00f7 7 = 12\/7 hours<\/strong>, the same answer as before. Both methods work, so test takers can use whichever approach they find easier to follow.<\/p>\n<p><br \/>\t<div  style='background:#ffffff;color:#444444;border-color:#333333;' class='av_promobox  avia-button-no   avia-builder-el-11  el_after_av_hr  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>4. Tracey ran to the top of a steep hill at an average pace of 6 miles per hour. She took the exact same trail back down. To her relief, the descent was much faster; her average speed rose to 14 miles per hour. If the entire run took Tracey exactly one hour to complete and she did not make any stops, how many miles is the trail one way?<\/p>\n<\/div><\/div><br \/><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-12  el_after_av_promobox  el_before_av_promobox \" ><section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-4\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-4\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-4\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>For the way up the hill, we know that D = 6mph x T.<br \/>For the way down the hill, we know that D = 14mph x T.<br \/>Since we went know that the distance up the hill was the same as the distance down the hill, we can pick a number for D. Let&#8217;s choose &#8220;84&#8221; since it is a multiple of both 6 and 14. \u00a0If 84 = 6mph x T, then we know that T = 14 hours. If 84 = 14mph x T, then we know that T\u00a0 = 6 hours.<br \/>Now we can use another formula, the Average Rate formula, to find the average speed for the WHOLE trip.\u00a0Average Rate = Total Distance \/ Total Time<br \/>Using our Picked Number of 84, we know that the Total Distance traveled would be 168 miles. The Total Time is 14 hours + 6 hours = 20 hours. \u00a0So the Average Rate = 168 miles \/ 20 hours = 8.4 mph.<br \/>It doesn&#8217;t matter that Tracey didn&#8217;t &#8220;really&#8221; go 168 miles, or that we know she didn&#8217;t &#8220;really&#8221; go 20 hours. We Picked a Number just so that we could find the ratio of the Total Distance to the Total Time in order to calculate the Average Rate of the ENTIRE journey.<br \/>Now that we have found the Average Rate for the whole trip, we can plug it in to the &#8220;DIRT&#8221; formula to find the ACTUAL distance for the entire journey.<br \/>D = R x T<br \/>D = 8.4mph x 1 hour<br \/>We know that T = 1 hour because the problem told us so. Therefore, the actual distance for the entire trip was 8.4 miles. The problem asks how many miles the trail was one way. 8.4 \/ 2 = 4.2. The answer to the question is 4.2 miles.<br \/>You could also solve this problem in other ways, including using a system of equations and substitution, but it&#8217;s nice to know that you can pick a number for the Distance traveled and use it to find the Average Rate for the whole journey!<\/p>\n            <\/div>        <\/div>    <\/div><\/section><\/div><\/p>\n<p>\u00a0<\/p>\n<h3>GRE Work Practice with Multiple Identical Machines<\/h3>\n<p>For identical workers or machines operating at the same constant rate, the work formula becomes:<\/p>\n<p><strong>Work = Number of workers \u00d7 Rate per worker \u00d7 Time<\/strong><\/p>\n<p>The first step is to find one worker\u2019s rate. That rate stays the same even when the number of workers changes.<\/p>\n\t<div  style='background:#ffffff;color:#444444;border-color:#333333;' class='av_promobox  avia-button-no   avia-builder-el-13  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p><strong>5. Nine identical machines, each working at the same constant rate, can stitch 27 jerseys in 4 minutes. How many minutes would it take 4 such machines to stitch 60 jerseys?<\/strong><\/p>\n<p>\n<\/div><\/div><br \/><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-14  el_after_av_promobox  el_before_av_promobox \" ><section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-5\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-5\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-5\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>Start by finding the rate of one machine:<\/p>\n<p>27 \u00f7 (9 \u00d7 4) = 3\/4 jersey per minute<\/p>\n<p>Then organize both situations in a table:<\/p>\n<table>\n<thead>\n<tr>\n<th>Situation<\/th>\n<th align=\"right\">Machines<\/th>\n<th align=\"right\">Rate per machine<\/th>\n<th align=\"right\">Time<\/th>\n<th align=\"right\">Total jerseys<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Original<\/td>\n<td align=\"right\">9<\/td>\n<td align=\"right\">3\/4 jersey per minute<\/td>\n<td align=\"right\">4 minutes<\/td>\n<td align=\"right\">27<\/td>\n<\/tr>\n<tr>\n<td>New<\/td>\n<td align=\"right\">4<\/td>\n<td align=\"right\">3\/4 jersey per minute<\/td>\n<td align=\"right\">t minutes<\/td>\n<td align=\"right\">60<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>\u00a0<\/p>\n<p>Four machines together produce:<\/p>\n<p>4 \u00d7 3\/4 = 3 jerseys per minute<\/p>\n<p>The time required to make 60 jerseys is:<\/p>\n<p><strong>60 \u00f7 3 = 20 minutes<\/strong><\/p>\n<p>When both the worker count and workload change, calculating the rate per worker helps prevent proportional-reasoning errors.<\/p>\n            <\/div>        <\/div>    <\/div><\/section><br><\/div><\/p>\n\n\n\n<h3>GRE Rate Practice with Different Starting Times<\/h3>\n\n\n\n<p>When two objects travel toward each other, their speeds add to give the rate at which the gap closes. If one starts earlier, first account for the distance it travels alone.<\/p>\n\n\n\t<div  style='background:#ffffff;color:#444444;border-color:#333333;' class='av_promobox  avia-button-no   avia-builder-el-15  el_after_av_toggle_container  el_before_av_toggle_container '>\t\t<div class='avia-promocontent'><p>6. Two stations are 300 miles apart. At noon, a train leaves the first station traveling toward the second at 240 miles per hour. At 12:10 p.m., another train leaves the second station traveling toward the first at 160 miles per hour. Assuming both maintain constant speeds, at what time do they meet?<\/p>\n<p>\n<\/div><\/div><br><div  class=\"togglecontainer   toggle_close_all  avia-builder-el-16  el_after_av_promobox  avia-builder-el-last \" ><\/p>\n\n\n<section class=\"av_toggle_section\"  itemscope=\"itemscope\" itemtype=\"https:\/\/schema.org\/BlogPosting\" itemprop=\"blogPost\"  >    <div role=\"tablist\" class=\"single_toggle\" data-tags=\"{All} \"  >        <p data-fake-id=\"#toggle-id-6\" class=\"toggler \"  itemprop=\"headline\"    role=\"tab\" tabindex=\"0\" aria-controls=\"toggle-id-6\">Explanation<span class=\"toggle_icon\" >        <span class=\"vert_icon\"><\/span><span class=\"hor_icon\"><\/span><\/span><\/p>        <div id=\"toggle-id-6\" class=\"toggle_wrap \"  >            <div class=\"toggle_content invers-color \"  itemprop=\"text\"   ><p>Break the trip into two stages.<\/p>\n<p><strong>Stage 1: Find the first train\u2019s head start.<\/strong><\/p>\n<p>Ten minutes equals 1\/6 hour, so the first train travels:<\/p>\n<p>240 \u00d7 1\/6 = 40 miles<\/p>\n<p>At 12:10 p.m., the trains are:<\/p>\n<p>300 \u2212 40 = 260 miles apart<\/p>\n<p><strong>Stage 2: Find how long the remaining gap takes to close.<\/strong><\/p>\n<p>Once both trains are moving, their combined closing speed is:<\/p>\n<p>240 + 160 = 400 miles per hour<\/p>\n<p>The time needed to close the gap is:<\/p>\n<p>260 \u00f7 400 = 0.65 hour = 39 minutes<\/p>\n<p>Adding 39 minutes to the second train\u2019s departure time gives <strong>12:49 p.m.<\/strong><\/p>\n<p>A common mistake is dividing the original 300-mile distance by the combined speed without accounting for the first train\u2019s head start.<\/p>\n            <\/div>        <\/div>    <\/div><\/section><br><\/div><\/p>\n","protected":false},"excerpt":{"rendered":"<p>On the GRE, Rates and Work questions may appear in any of the Quantitative question formats: Multiple Choice, Numeric Entry, or Quantitative Comparisons. A \u201crate\u201d is anything\u00a0per\u00a0anything (miles per hour, laps per minute, gallons of paint per square inch of wall, etc.).In the meantime, here are two formulas you should memorize to get these types [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":28926,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[68],"tags":[],"_links":{"self":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/2415"}],"collection":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/comments?post=2415"}],"version-history":[{"count":7,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/2415\/revisions"}],"predecessor-version":[{"id":50442,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/posts\/2415\/revisions\/50442"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/media\/28926"}],"wp:attachment":[{"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/media?parent=2415"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/categories?post=2415"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/wpapp.kaptest.com\/study\/wp-json\/wp\/v2\/tags?post=2415"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}